How to use the PERMUTATIONA function

What is the PERMUTATIONA function?

The PERMUTATIONA function returns the number of permutations for a specific number of elements that can be selected from a larger group of elements. Repetition is allowed.

1. Introduction

Explain what a permutation is?

A permutation is a way of arranging a set of elements in a specific order. For example, if you have three letters A, B, and C, you can arrange them in six different ways: ABC, ACB, BAC, BCA, CAB, and CBA.

Each of these arrangements is called a permutation of the three letters. The order of the objects matters in a permutation, so ABC and BAC are considered different permutations.

What is repetition allowed?

Repetition allowed is when there can be duplicate values. A phone number is a great example of a permutation that may contain duplicate digits.

What is an element?

An element refers to an item which can be anything.

What is the difference between the PERMUTATIONA function and the PERMUT function?

PERMUTATIONA allows repetition, PERMUT does not.

PERMUTATIONA calculates the number of permutations for a given number of objects (n) selected from a pool of objects where order is important and objects can repeat.

PERMUT calculates the number of permutations for a given number of objects (n) selected from a pool of unique objects where order is important but repetition is not allowed.

How can I create a list of permutations with repetition?

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What is the difference between combination and permutation?

Combinations: Order does not matter. ABC and BAC are considered the same.
Permutations - Order matters. ABC is different from BAC.

Permutations are used when order matters - like sequences, orders, arrangements.
Combinations are used when specific groupings matter but order doesn't - like teams, packs, sets.

How can I create a list of permutations without repetition?

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Related functions

Excel Function and Arguments	Description
PERMUT(number, number_chosen)	Returns the number of permutations for a given number of objects selected from number items without repetition
PERMUTATIONA(number, number_chosen)	Returns the number of permutations for a given number of objects selected from number items with repetition allowed
COMBIN(number, number_chosen)	Returns the number of combinations for a given number of objects selected from number items without repetition
COMBINA(number, number_chosen)	Returns the number of combinations for a given number of objects selected from number items with repetition allowed

2. PERMUTATIONA Function Syntax

PERMUTATIONA(number, number-chosen)

3. PERMUTATIONA Function Arguments

number	The total number of elements.
number-chosen	A specific number of elements.

4. PERMUTATIONA function Example

A jewelry designer is creating a new bracelet design with two different gemstones. The available gemstones are ruby, emerald, and sapphire. If the order of the gemstones matters and repetition is allowed, how many different bracelet designs can be created?

The picture above shows permutations with repetition allowed, 2 out of 3 gemstones.

Formula in cell D3:

The formula returns 9 different bracelet designs can be created.

5. Create a list of permutations - Excel 365

A manufacturing company has four different types of metals available (A, B, C, and D), repetition is allowed. They want to explore various permutations by arranging two metals together. The goal is to determine all the possible arrangements or permutations that can be formed by selecting two metals at a time from the four available options.

To calculate the number of permutations and list them out, we can use the following approach:

Total number of metals = 4
Number of metals to be selected for each arrangement = 2
We can use the PERMUT function to calculate the number of permutations:

=PERMUTATONA(n,r)

Where:
n = the total number of items (in this case, metals)
r = the number of items being selected or arranged

Substituting the values:
n = 4 (four different metals)
r = 2 (selecting two metals for each arrangement)

The result is 16 different permutations.

The Excel 365 dynamic formula in cell I3 creates a list of permutations with repetition, I demonstrate a formula that creates permutations without repetition below.

Formula in cell I3:

This formula is dynamic meaning it spills to more or fewer cells automatically if you change the numbers in cells F5 and F6.

Explaining formula

Step 1 - Calculate items in list

The PERMUTATIONA function returns the number of permutations for a specific number of elements that can be selected from a larger group of elements. Repetition is allowed.

PERMUTATIONA(number, number-chosen)

PERMUTATIONA(F5, F6)

becomes

PERMUTATIONA(4, 2)

and returns 16.

Step 2 - Create a list of sequential numbers

The SEQUENCE function creates a list of sequential numbers to a cell range or array.

SEQUENCE(rows, [columns], [start], [step])

SEQUENCE(PERMUTATIONA(F5,F6))-1

becomes

SEQUENCE(16)-1

becomes

{1; 2; 3; 4; 5; 6; 7; 8; 9; 10; 11; 12; 13; 14; 15; 16}-1

and returns

{0; 1; 2; 3; 4; 5; 6; 7; 8; 9; 10; 11; 12; 13; 14; 15}

Step 3 - Number raised to a power

^ character lets you raise a number to a power of a given number. It is the same as the POWER function but shorter.

F5^(SEQUENCE(,F6,F6-1,-1)+1)

becomes

F5^(SEQUENCE(,2,1,-1)+1)

becomes

F5^({1, 0}+1)

becomes

4^{2, 1}

and returns {16, 4}.

Step 4 - Calculate remainder

The MOD function returns the remainder after a number is divided by a divisor.

MOD(number, divisor)

MOD(SEQUENCE(PERMUTATIONA(F5,F6))-1,F5^(SEQUENCE(,F6,F6-1,-1)+1))

becomes

MOD({0; 1; 2; 3; 4; 5; 6; 7; 8; 9; 10; 11; 12; 13; 14; 15},{16, 4})

and returns

{0, 0; 1, 1; 2, 2; 3, 3; 4, 0; 5, 1; 6, 2; 7, 3; 8, 0; 9, 1; 10, 2; 11, 3; 12, 0; 13, 1; 14, 2; 15, 3}.

Step 5 - Round numbers down

Thr FLOOR function rounds a number down, toward zero, to the nearest multiple of significance.

FLOOR(number, significance)

FLOOR(MOD(SEQUENCE(PERMUTATIONA(F5,F6))-1,F5^(SEQUENCE(,F6,F6-1,-1)+1))/(F5^SEQUENCE(,F6,F6-1,-1)),1)+1

becomes

FLOOR({0, 0; 1, 1; 2, 2; 3, 3; 4, 0; 5, 1; 6, 2; 7, 3; 8, 0; 9, 1; 10, 2; 11, 3; 12, 0; 13, 1; 14, 2; 15, 3}/({4,1}),1)+1

becomes

FLOOR({0, 0; 0.25, 1; 0.5, 2; 0.75, 3; 1, 0; 1.25, 1; 1.5, 2; 1.75, 3; 2, 0; 2.25, 1; 2.5, 2; 2.75, 3; 3, 0; 3.25, 1; 3.5, 2; 3.75, 3},1)+1

becomes

{0, 0; 0, 1; 0, 2; 0, 3; 1, 0; 1, 1; 1, 2; 1, 3; 2, 0; 2, 1; 2, 2; 2, 3; 3, 0; 3, 1; 3, 2; 3, 3}+1

and returns

{1, 1; 1, 2; 1, 3; 1, 4; 2, 1; 2, 2; 2, 3; 2, 4; 3, 1; 3, 2; 3, 3; 3, 4; 4, 1; 4, 2; 4, 3; 4, 4}.

Step 6 - Get values

The INDEX function gets a value based on a row number and column number (optional).

INDEX(array, [row_num], [column_num], [area_num])

INDEX(B3:E3,FLOOR(MOD(SEQUENCE(PERMUTATIONA(F5,F6))-1,F5^(SEQUENCE(,F6,F6-1,-1)+1))/(F5^SEQUENCE(,F6,F6-1,-1)),1)+1)

becomes

INDEX(B3:E3, {1, 1; 1, 2; 1, 3; 1, 4; 2, 1; 2, 2; 2, 3; 2, 4; 3, 1; 3, 2; 3, 3; 3, 4; 4, 1; 4, 2; 4, 3; 4, 4})

becomes

INDEX({"A","B","C","D"}, {1, 1; 1, 2; 1, 3; 1, 4; 2, 1; 2, 2; 2, 3; 2, 4; 3, 1; 3, 2; 3, 3; 3, 4; 4, 1; 4, 2; 4, 3; 4, 4})

and returns

{"A", "A"; "A", "B"; "A", "C"; "A", "D"; "B", "A"; "B", "B"; "B", "C"; "B", "D"; "C", "A"; "C", "B"; "C", "C"; "C", "D"; "D", "A"; "D", "B"; "D", "C"; "D", "D"}.

Step 7 - Shorten formula

The LET function lets you name intermediate calculation results which can shorten formulas considerably and improve performance.

LET(name1, name_value1, calculation_or_name2, [name_value2, calculation_or_name3...])

INDEX(B3:E3, FLOOR(MOD(SEQUENCE(PERMUTATIONA(F5,F6))-1,F5^(SEQUENCE(,F6,F6-1,-1)+1))/(F5^SEQUENCE(,F6,F6-1,-1)),1)+1)

becomes

LET(y, F6, x, SEQUENCE(,y,y-1,-1), INDEX(B3:E3,FLOOR(MOD(SEQUENCE(PERMUTATIONA(F5,y))-1,F5^(x+1))/(F5^x),1)+1))

Recommended articles
List permutations with repetition [UDF]
Create permutations [UDF]
Permutations with and without repetition
List all permutations with a condition

 

6. PERMUTATIONA function not working

The PERMUTATIONA function returns:

• #NUM! error value if numeric arguments are values that are not valid.
• #VALUE! error value if numeric arguments use data types that are nonnumeric.

7. List permutations with repetition and how many to choose from

This section demonstrates a macro that lets you create a list of permutations, repetitions are allowed, based on a number of comma-delimited strings and the number of items per row.

The image above shows a list created by the macro based on numbers 1, 2, and 3 and five items per row.

Table of Contents

1. Question
2. VBA code
3. Where to copy code?
4. How to run the macro?
5. How to use the macro?
6. List permutations with repetition and how many to choose from (Excel 365 formula)
7. Get the Excel File here

Noel asks:

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7.2. VBA code

The following macro lets you enter text strings separated by a comma and the number of games.

 

Sub ListPermut()
'This macro creates a list of all permutations
'Get digital Help - https://www.get-digital-help.com/

'Define variables
Dim ws As Worksheet, Ans As String, ans1() As String, digits As Integer
Dim num As Integer, p As Long, i As Long, t As Long
Dim rng() As Long, c As Long, rng1() As String

'Insert a new sheet
Set ws = Sheets.Add

'Ask for user input
Ans = InputBox("Type strings separated with a comma:")
digits = InputBox("How many strings?")

'Split text strings to an array
ans1 = Split(Ans, ",")

'Count values in aray
num = UBound(ans1) + 1

'Calculate number of permutations
p = num ^ digits

'Redimension arrays
ReDim rng(1 To digits)
ReDim rng1(1 To digits)

'Save 1 to all values in first row of array
For c = 1 To digits
rng(c) = 1
Next c

i = 0

'Don't show the result until finished
Application.ScreenUpdating = False

'Repeat until all permutations have been created
Do Until (i + t) = (p - 1)
'Use text strings instead of numbers
For c = LBound(rng1) To UBound(rng1)
rng1(c) = ans1(rng(c) - 1)
Next c
'Transfer values from array to worksheet
ws.Range("A1").Resize(, digits).Offset(i) = rng1

'Build next row of permutations
For c = digits To 1 Step -1
If c = digits Then
rng(c) = rng(c) + 1
ElseIf rng(c) = 0 Then
rng(c) = rng(c - 1)
End If
If rng(c) = num + 1 Then
rng(c) = 1
rng(c - 1) = rng(c - 1) + 1
End If
Next c

'Count made permutations
i = i + 1

'Insert a new sheet if rows exceed 999 999
If i = 1000000 Then
Set ws = Sheets.Add
t = t + 1000000
i = 0
End If

Loop
'Use text strings instead of numbers
For c = LBound(rng1) To UBound(rng1)
rng1(c) = ans1(rng(c) - 1)
Next c
'Transfer values from array to worksheet
ws.Range("A1").Resize(, digits).Offset(i) = rng1
'Show output
Application.ScreenUpdating = True

End Sub

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7.3. Where to copy code?

1. Press Alt-F11 to open visual basic editor
2. Press with left mouse button on Module on the Insert menu
3. Copy and paste code above to the code module
   
4. Exit visual basic editor (Alt+Q)

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7.4. How to run the macro?

1. Press Alt+F8 to open the macro dialog box
2. Press with left mouse button on ListPermut macro
3. Press with left mouse button on Run.

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7.5. How to use the macro?

Enter your text strings using a comma as a text delimiting character.

Press with left mouse button on OK button.

Enter number of games.

Press with left mouse button on OK button.

Excel processes the data for a while and then creates two sheets with a total of 1594323 permutations.

The picture shows 14 out of 1594323 permutations.

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7.6. List permutations with repetition and how many to choose from (Excel 365 formula)

The Excel 365 formula in cell C3 spills to other adjacent cells automatically based on the values in the Excel Table (cell range I3:I5) and the number entered in cell K3.

You can add and delete strings in cell range I3:I5, the only limit is the worksheet row limit of 1 048 576. For example, 3 strings and 13 items return 1 594 323 rows and won't fit a worksheet.

You have to move the Excel Table and the value in cell K3 if you have more than 6 items, the Excel 365 formula returns a #SPILL! error if adjacent cells are populated.

Excel 365 dynamic array formula in cell C3:

Excel 365 formula in cell B3:

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8. List all permutations with a condition

I got a question a while ago about permutations, in essence how to find every permutation between 0 and 9 000 000 000 with a condition, if the sum of all digits in a number is smaller or equal to 9.

You can read about the difference between combinations and permutations here: Return all combinations but in short, the order is important for permutations and not important for combinations.

This number 303 030 000 is equal to 9 if you sum every digit, 3+0+3+0+3+0+0+0+0 = 9. 92 is above 9, 9+2 = 11 and is not a number we are looking for.

8.1. Sum all digits in a number - User Defined Function (UDF)

The following user-defined function named  SumChr adds all digits in a number and returns the total. The image above demonstrates the SumChr function in column B.

For example, number 92 in cell A3 contains two digits, 9 and 2. The total is 9 + 2 equals 11. The SumChr function returns 11 in cell B3.

'Name User Defined Function and specify parameters
Function SumChr(nmbr As Long)

'Dimension variables and declare data types
Dim sm As Long

'For ... Next statement
For i = 1 To Len(CStr(nmbr))

'Add number to total and save the total
sm = sm + Val(Mid(nmbr, i, 1))

'Continue with next digit
Next i

'Return total to worksheet
SumChr = sm
End Function

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8.2. Sum all digits in a number (formula)

Formula in cell C3:

Excel 365 dynamic array formula in cell C3:

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8.3. Generate permutations based on a condition (slow UDF)

It is easy to iterate through every number between 0 and for example 10 000 000 and check if the digit sum is smaller or equal to 9. The UDF below does that.

The picture above shows all numbers between 0 and 20 where the digit sum is smaller or equal to 9, the CalcVal function above made this list.

Number 19 is missing, 1+9 = 10. 10 is bigger than 9. Column B contains the digit sum, except cell B1. It has the time it took to calculate the list. In this case, it took almost no time at all, and excel rounded it to 0 (zero).

'Name User Defined Function and specify parameters
Function CalcVal(k As Double)

'Dimension variables and declare data types
Dim i As Long, j() As Double, a As Double

'Redimension array variable j
ReDim j(0 To 60000, 1)

'Save timer value to variable a
a = Timer

'Save 0 (zero) to variable l
l = 0

'For ... Next statement
'Iterate from 0 (zero) to number stored in variable k
For i = 0 To k

'Calculate total using UDF SumChr based on number stored in variable i
m = SumChr(i)

Check if variable m is equal to 9
If m <= 9 Then

'Save value stored in variable i to array variable j
j(l, 0) = i

'Save value stored in variable m to array variable j
j(l, 1) = m

'Add one to value stored in variable l and save to variable l
l = l + 1
End If
Next i

'Calculate time needed calculate result and save to array variable j
j(0, 1) = Timer - a

'Return array variable j to worksheet
CalcVal = j()
End Function

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8.4. Generate permutations based on a condition (faster UDF)

The problem is if you try to do the same with a really large range of numbers, it will take a very long time to calculate for a desktop pc. This UDF shortens that time considerably.

'Name User Defined Function and specify parameters
Function CalcVal1(k As Single)

'Dimension variables and declare data types
Dim i As Single, j() As Double, a As Double
Dim l As Single, m As Single

'Save time value to variable a
a = Timer

'Redimension array variable j
ReDim j(0 To 2000000, 1)

'Save -1 to variable i and 0 (zero) to variable m
i = -1: m = 0

'Do Until ... Loop
'Keep iterating until number in variable k is maller than or equal to number in variable i
Do Until k <= i

'If ... Then .. ElseIf .. Endif statement
'Check if total is equal to or less than 9
If SumChr(i) <= 9 Then

'Convert variable i to string and then count characters in string, save number of characters to variable p
p = Len(CStr(i))

'For ... Next statement
'Go backwards from number of characters in variable i to 1
For l = Len(CStr(i)) To 1 Step -1

'If ... Then ... ElseIf ... Esle ... End If statement
'Check if characters is not equal to 0 (zero) and not equal to 9
If Mid(i, l, 1) <> 0 And Mid(i, l, 1) <> 9 Then

'Replace character in string
i = Val(ReplaceChrInStr(i, l, 0))
i = Val(ReplaceChrInStr(i, l - 1, Mid(i, l - 1, 1) + 1))
Exit For
ElseIf Mid(i, l, 1) = 9 Then
i = i + Application.WorksheetFunction.Power(10, Len(CStr(i)) - 1)
Exit For
End If
Next l
Else
i = i + 1
End If
If i < k Then
j(m, 0) = i
Else
j(m, 0) = ""
End If
j(m, 1) = SumChr(i)
m = m + 1
Loop
j(0, 1) = Timer - a
CalcVal1 = j
End Function

Function ReplaceChrInStr(tmp As String, pos As Single, chr As String)
Dim str As String, i As Single
For i = 1 To Len(tmp)
    If i = pos Then
        str = str & chr
    Else
        str = str & Mid(tmp, i, 1)
    End If
Next i
ReplaceChrInStr = str
End Function

The UDF basically examines each digit in a number and if the sum is 9 these things happens:

• If digit is not equal to 9 and zero, make that digit a 0 and add 1 to the next digit.
• If digit is equal to 9, add 1,10, 100... depending on the position (n) the digit has in the number. Example, digit 9 in number 90 is the second digit counting from right to left, n=2. 10^(2-1) is 10. 90+10 = 100

If the digit sum is not equal to 9 the udf adds 1 to the current number and the loop continues until the entire range has been created.

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8.5. Comparing custom functions

Now lets compare the run times of the two udfs CalcVal and CalcVal1.

For smaller ranges like 0 - 9000 CalcVal is faster, somewhere around perhaps 5000 CalcVal1 seems to take the lead.

I am using an old laptop with a dual-core intel i3 cpu, I am getting 29% utilization. I don't know why, it seems that only one core is utilized by excel. In any case, the numbers indicate that the CalcVal1 function is much faster.

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8.6. Where to put the code?

1. Press Alt + F11 to open the Visual Basic Editor (VBE).
2. Press with mouse on "Insert" on the top menu.
3. Press with mouse on "Module".
4. Copy above UDFs and paste to the code window.
5. Return to Excel

'PERMUTATIONA' function examples

Functions in 'Statistical' category

The PERMUTATIONA function function is one of 73 functions in the 'Statistical' category.

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